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Author Topic:  Alex's images  (Read 1343 times)

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Offline FractalAlex

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Re: Alex's images
« Reply #30 on: February 22, 2021, 02:10:26 AM »
Next, the tanc function

\( f(z) = tanc(z) \)
"I am lightning, the rain transformed."
- Raiden, Metal Gear Solid 4: Guns of the Patriots

Offline FractalAlex

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Re: Alex's images
« Reply #31 on: February 22, 2021, 02:11:05 AM »
And lastly, the tanhc function.

\( f(z) = tanhc(z) \)

Offline FractalAlex

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Re: Alex's images
« Reply #32 on: February 25, 2021, 09:52:53 PM »
Here is a Nova fractal, for the function \( f(z) = \zeta(z) \), also known as the Riemann zeta function, where \( \zeta(z) = \sum_{n=1}^{\infty} \frac{1}{n^z}. \) For simplification, the function is \( f(z) = ze^{-z}. \)

Offline gerrit

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Re: Alex's images
« Reply #33 on: Yesterday at 02:25:20 AM »
Here is a Nova fractal, for the function \( f(z) = \zeta(z) \), also known as the Riemann zeta function, where \( \zeta(z) = \sum_{n=1}^{\infty} \frac{1}{n^z}. \) For simplification, the function is \( f(z) = ze^{-z}. \)
So if it's \( f(z) = ze^{-z} \) what does it have to do with the zeta function?

Offline FractalAlex

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Re: Alex's images
« Reply #34 on: Yesterday at 11:37:42 AM »
See here for an explanation: https://www.dhushara.com/DarkHeart/geozeta/zetageo.htm
That's where I got the function. Unfortunately I couldn't use the sum notation in Ultra Fractal's formula editor.


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