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Author Topic: (Other) Perpendicular burning ship with arbitrary exponent  (Read 703 times)

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Offline therror

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(Other) Perpendicular burning ship with arbitrary exponent
« on: February 23, 2018, 03:39:26 PM »
The fractal is rendered with power from -8 to +8 and then rotated to "vertical" format (y is exponent) and finally it is revolving around the exponent axis.

The code:

Code: [Select]
x2=xold*xold;
y2=yold*yold;
po=__powf((x2+y2), 0.5f*pwr);
at=pwr*atan2f(((yold<0)?-yold:yold), xold);
xnew=po*__cosf(at)+re;
ynew=-po*__sinf(at)+im;

https://youtu.be/F5UzljA030k

Linkback: https://fractalforums.org/fractal-movie-gallery/19/perpendicular-burning-ship-with-arbitrary-exponent/920/

Offline therror

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Re: Perpendicular burning ship with arbitrary exponent
« Reply #1 on: February 23, 2018, 05:07:14 PM »
Colouring:
Exterior -escape time
Interior - periodicity detection.
Distance estimation would be perfect, but I don't know how to do it.

Offline greentexas

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Re: Perpendicular burning ship with arbitrary exponent
« Reply #2 on: February 24, 2018, 02:35:56 AM »
Well done!

I have an idea:

I know that you can do the Perpendicular Mandelbrot and the Heart by either doing a hybrid of Mandelbrot/BS or by multiplying the fractal by some power of i.

Off the top of my head, I also know that a real Buffalo and imaginary of this fractal gives the Perpendicular Buffalo.

Offline therror

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Re: Perpendicular burning ship with arbitrary exponent
« Reply #3 on: February 24, 2018, 01:16:52 PM »
I think about multi-buffalo, but I am confused: imaginary part of buffalo is abs(im) of Mandelbrot multiplied by -1, while this of cubic buffalo is simply  abs(im) of Mandelbrot(3th).

Offline greentexas

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Re: Perpendicular burning ship with arbitrary exponent
« Reply #4 on: February 24, 2018, 02:24:37 PM »
You could do the formula for a Buffalo fractal in the complex plane with abs(zn) + z0.

Offline therror

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Re: Perpendicular burning ship with arbitrary exponent
« Reply #5 on: February 27, 2018, 06:53:09 PM »
Multu-Buffalo is ready. 2th, 3th and 5th. Movie will be done later. It seems 2th incorrect because buffalo uses -2*abs instead 2* abs in Im part.

Offline greentexas

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Re: Perpendicular burning ship with arbitrary exponent
« Reply #6 on: February 28, 2018, 04:04:33 AM »
Actually, those pictures are entirely correct. If you're looking for a Buffalo that is the way you want it e.g. this image, you'll have to negate the imaginary side.

The image is here: https://softologyblog.wordpress.com/2016/09/18/custom-formula-editor-for-visions-of-chaos/

Offline therror

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Re: Perpendicular burning ship with arbitrary exponent
« Reply #7 on: November 09, 2018, 10:19:26 AM »
The same for Buffalo
https://youtu.be/6fOM6LDgTL4


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